Quantity is how many containers you have. The result is how many tributaries fit, the path, and the leftover line rate. The choices stay in the URL, so you can share them.
Result: standard mapping
How many E0s are in an OTU2?
An OTU2 carries 120,960 E0s, per ITU-T G.709, ITU-T G.707 and ITU-T G.704. This path maps STM-64 into ODU2 as a client, then follows that client's tributaries.
120,960
E0s in an OTU2
Working
OTU2 → 1 × ODU2 → 1 × STM-64 → 64 × STM-1 → 63 × E1 → 30 × E0
- 1 × ODU2 in each OTU2 ITU-T G.709The OTU2 frame carries exactly one ODU2.
- 1 × STM-64 in each ODU2 ITU-T G.709Client mappingCBR STM-64 mapped into OPU2.
- 64 × STM-1 in each STM-64 ITU-T G.70764 × STM-1.
- 63 × E1 in each STM-1 ITU-T G.70763 VC-12 tributaries: 3 TUG-3 × 7 TUG-2 × 3 TU-12.
- 30 × E0 in each E1 ITU-T G.70430 voice channels in 32 timeslots. TS0 is framing and TS16 is channel-associated signalling.
- 1 ODU2
- 1 × 1 = 1 STM-64
- 1 × 1 × 64 = 64 STM-1s
- 1 × 1 × 64 × 63 = 4,032 E1s
- 1 × 1 × 64 × 63 × 30 = 120,960 E0s
Leftover capacity
2.967785316 Gbit/s of each OTU2 line rate (10.709225316 Gbit/s) sits outside 120,960 × 64 kbit/s of E0 line rate (7.741440 Gbit/s). That remainder is overhead, fixed stuff or justification. It is not another whole tributary.
By bit rate only
Dividing the line rates gives 167,331.64, which floors to 167,331 E0s by bit rate only. The standard mapping is 120,960. Use the mapping.
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