Quantity is how many containers you have. The result is how many tributaries fit, the path, and the leftover line rate. The choices stay in the URL, so you can share them.

Result: standard mapping

How many DS0s are in an OTU1?

An OTU1 carries 32,256 DS0s, per ITU-T G.709, ITU-T G.707 and ANSI T1.107. This path maps STM-16 into ODU1 as a client, then follows that client's tributaries.

32,256

DS0s in an OTU1

Working

OTU1 → 1 × ODU1 → 1 × STM-16 → 16 × STM-1 → 84 × DS1 → 24 × DS0

1 × ODU1 in each OTU1 ITU-T G.709The OTU1 frame carries exactly one ODU1. The line-rate gap is OTU overhead and FEC.
1 × STM-16 in each ODU1 ITU-T G.709Client mappingCBR STM-16 mapped into OPU1.
16 × STM-1 in each STM-16 ITU-T G.70716 × STM-1.
84 × DS1 in each STM-1 ITU-T G.70784 VC-11 tributaries: 3 TUG-3 × 7 TUG-2 × 4 TU-11.
24 × DS0 in each DS1 ANSI T1.10724 payload timeslots. The framing bit adds 8 kbit/s and brings the line rate to 1.544 Mbit/s.

1 ODU1
1 × 1 = 1 STM-16
1 × 1 × 16 = 16 STM-1s
1 × 1 × 16 × 84 = 1,344 DS1s
1 × 1 × 16 × 84 × 24 = 32,256 DS0s

Leftover capacity

601.673143 Mbit/s of each OTU1 line rate (2.666057143 Gbit/s) sits outside 32,256 × 64 kbit/s of DS0 line rate (2.064384 Gbit/s). That remainder is overhead, fixed stuff or justification. It is not another whole tributary.

By bit rate only

Dividing the line rates gives 41,657.14, which floors to 41,657 DS0s by bit rate only. The standard mapping is 32,256. Use the mapping.

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