Quantity is how many containers you have. The result is how many tributaries fit, the path, and the leftover line rate. The choices stay in the URL, so you can share them.
Result: standard mapping
How many E0s are in an ODU3?
An ODU3 carries 483,840 E0s, per ITU-T G.709, ITU-T G.707 and ITU-T G.704. This path maps STM-256 into ODU3 as a client, then follows that client's tributaries.
483,840
E0s in an ODU3
Working
ODU3 → 1 × STM-256 → 256 × STM-1 → 63 × E1 → 30 × E0
- 1 × STM-256 in each ODU3 ITU-T G.709Client mappingCBR STM-256 mapped into OPU3.
- 256 × STM-1 in each STM-256 ITU-T G.707256 × STM-1.
- 63 × E1 in each STM-1 ITU-T G.70763 VC-12 tributaries: 3 TUG-3 × 7 TUG-2 × 3 TU-12.
- 30 × E0 in each E1 ITU-T G.70430 voice channels in 32 timeslots. TS0 is framing and TS16 is channel-associated signalling.
- 1 STM-256
- 1 × 256 = 256 STM-1s
- 1 × 256 × 63 = 16,128 E1s
- 1 × 256 × 63 × 30 = 483,840 E0s
Leftover capacity
9.353458983 Gbit/s of each ODU3 line rate (40.319218983 Gbit/s) sits outside 483,840 × 64 kbit/s of E0 line rate (30.965760 Gbit/s). That remainder is overhead, fixed stuff or justification. It is not another whole tributary.
By bit rate only
Dividing the line rates gives 629,987.79, which floors to 629,987 E0s by bit rate only. The standard mapping is 483,840. Use the mapping.
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